Optimal. Leaf size=59 \[ \frac{\left (a^2-b^2\right ) \tanh ^{-1}(\sin (c+d x))}{2 d}+\frac{\sec ^2(c+d x) (a \sin (c+d x)+b) (a+b \sin (c+d x))}{2 d} \]
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Rubi [A] time = 0.0612642, antiderivative size = 59, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 3, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.143, Rules used = {2668, 723, 206} \[ \frac{\left (a^2-b^2\right ) \tanh ^{-1}(\sin (c+d x))}{2 d}+\frac{\sec ^2(c+d x) (a \sin (c+d x)+b) (a+b \sin (c+d x))}{2 d} \]
Antiderivative was successfully verified.
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Rule 2668
Rule 723
Rule 206
Rubi steps
\begin{align*} \int \sec ^3(c+d x) (a+b \sin (c+d x))^2 \, dx &=\frac{b^3 \operatorname{Subst}\left (\int \frac{(a+x)^2}{\left (b^2-x^2\right )^2} \, dx,x,b \sin (c+d x)\right )}{d}\\ &=\frac{\sec ^2(c+d x) (b+a \sin (c+d x)) (a+b \sin (c+d x))}{2 d}+\frac{\left (b \left (a^2-b^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{b^2-x^2} \, dx,x,b \sin (c+d x)\right )}{2 d}\\ &=\frac{\left (a^2-b^2\right ) \tanh ^{-1}(\sin (c+d x))}{2 d}+\frac{\sec ^2(c+d x) (b+a \sin (c+d x)) (a+b \sin (c+d x))}{2 d}\\ \end{align*}
Mathematica [A] time = 0.942801, size = 113, normalized size = 1.92 \[ \frac{\left (4 a b^3-6 a^3 b\right ) \tan ^2(c+d x)+\left (a^2-b^2\right )^2 (\log (1-\sin (c+d x))-\log (\sin (c+d x)+1))-2 \left (a^4-b^4\right ) \tan (c+d x) \sec (c+d x)+2 a^3 b \sec ^2(c+d x)}{4 d \left (b^2-a^2\right )} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.055, size = 118, normalized size = 2. \begin{align*}{\frac{{a}^{2}\sec \left ( dx+c \right ) \tan \left ( dx+c \right ) }{2\,d}}+{\frac{{a}^{2}\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{2\,d}}+{\frac{ab}{d \left ( \cos \left ( dx+c \right ) \right ) ^{2}}}+{\frac{{b}^{2} \left ( \sin \left ( dx+c \right ) \right ) ^{3}}{2\,d \left ( \cos \left ( dx+c \right ) \right ) ^{2}}}+{\frac{{b}^{2}\sin \left ( dx+c \right ) }{2\,d}}-{\frac{{b}^{2}\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{2\,d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0.956641, size = 105, normalized size = 1.78 \begin{align*} \frac{{\left (a^{2} - b^{2}\right )} \log \left (\sin \left (d x + c\right ) + 1\right ) -{\left (a^{2} - b^{2}\right )} \log \left (\sin \left (d x + c\right ) - 1\right ) - \frac{2 \,{\left (2 \, a b +{\left (a^{2} + b^{2}\right )} \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{2} - 1}}{4 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.23095, size = 221, normalized size = 3.75 \begin{align*} \frac{{\left (a^{2} - b^{2}\right )} \cos \left (d x + c\right )^{2} \log \left (\sin \left (d x + c\right ) + 1\right ) -{\left (a^{2} - b^{2}\right )} \cos \left (d x + c\right )^{2} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 4 \, a b + 2 \,{\left (a^{2} + b^{2}\right )} \sin \left (d x + c\right )}{4 \, d \cos \left (d x + c\right )^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.15026, size = 116, normalized size = 1.97 \begin{align*} \frac{{\left (a^{2} - b^{2}\right )} \log \left ({\left | \sin \left (d x + c\right ) + 1 \right |}\right ) -{\left (a^{2} - b^{2}\right )} \log \left ({\left | \sin \left (d x + c\right ) - 1 \right |}\right ) - \frac{2 \,{\left (a^{2} \sin \left (d x + c\right ) + b^{2} \sin \left (d x + c\right ) + 2 \, a b\right )}}{\sin \left (d x + c\right )^{2} - 1}}{4 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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